Question: Math

x^2 +4x+3=0 Solve

In Math | Asked by AnneS2
Answers

x^2 +4x+3=0

(x   )(x   )   (   +1)(   +3)=0

(x+1) (x+3) = 0

Solve:

(x+1)=0

x+1-1=0-1

x=-1

Solve:

(x+3) = 0

x+3-3 = 0-3

x=-3

CherieS | 488 days ago