http://upload.wikimedia.org/math/8/c/5/8c58ae2d322a33f3036800d96db0e91a.png

x=(-b +/- sqrt(b^2-4ac))/2a

First you look Which numbers are ABC. example

aX**²+**bx+c

you have to find D

D=b**²**-(4ac

x= (-b+**√D)/2A or (-b- √D)/2A **

**hope i could help you.**

x = -b±√(b²-4ac)÷2ac

-b±√b2-4ac

2a

The "Quadratic Formula" is the formula used to solve a "Quadratic Equation" -- an equation of the form:

ax2 + bx + c = 0

The formula to find "x" is:

x = (-b+sqrt(b^2-4ac))/(2a) and

x = (-b-sqrt(b^2-4ac))/(2a)

In other words, you're trying to find what value or values of "x" would make the above equation TRUE, given the values of a, b, and c are known. For example:

1x2 - 1x - 2 = 0

is a Quadratic Equation, where a=1, b=-1, and c=-2. Using the Quadratic Formula, we get x = 2, and x = -1. If you substitute 2 or -1 into the original equation, you will see that the equation is true in both cases.

Keep in mind that there are quadratic equations that DO NOT have REAL solutions -- only IMAGINARY ones. I'm guessing that this is beyond what you're asking, so I will stop right here.

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