x=(-b +/- sqrt(b^2-4ac))/2a
First you look Which numbers are ABC. example
you have to find D
x= (-b+√D)/2A or (-b-√D)/2A
hope i could help you.
x = -b±√(b²-4ac)÷2ac
The "Quadratic Formula" is the formula used to solve a "Quadratic Equation" -- an equation of the form:
ax2 + bx + c = 0
The formula to find "x" is:
x = (-b+sqrt(b^2-4ac))/(2a) and
x = (-b-sqrt(b^2-4ac))/(2a)
In other words, you're trying to find what value or values of "x" would make the above equation TRUE, given the values of a, b, and c are known. For example:
1x2 - 1x - 2 = 0
is a Quadratic Equation, where a=1, b=-1, and c=-2. Using the Quadratic Formula, we get x = 2, and x = -1. If you substitute 2 or -1 into the original equation, you will see that the equation is true in both cases.
Keep in mind that there are quadratic equations that DO NOT have REAL solutions -- only IMAGINARY ones. I'm guessing that this is beyond what you're asking, so I will stop right here.
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