Math Factor and solve: 1x^2 + 13x + 40 = 0 Asked by AnneS2 on 10 Oct 06:42 Last updated by anonymous on 11 Oct 06:07

1x^2 + 13x + 40 = 0 (x )(x ) ( +5)( +8)=0 (x+5) (x+8) = 0 Solve: (x+5) =0 x+5-5 =0-5 x=-5 Solve: (x+8) = 0 x+8-8 = 0-8 x=-8