Question: Math

b^2 -4b+4=0

In Math | Asked by AnneS2
Answers

b^2 -4b+4=0

(b  )(b  )  (  -2)(  -2)=0

(b-2)(b-2)=0

(b-2)^2 = 0

Solve:

(b-2)=0

b-2+2=0+2

b=2

CherieS | 467 days ago