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Question: Math

Solve for both systems: 2x+7z=116 and 2x + 3z = 52

In Math | Asked by AnneS2
Answers

2x+7z=116

2x+7z-7z=116-7z

2x=116-7z

2x/2=116-7z/2

x=58-3.5z

2x + 3z = 52

2(58-3.5z) + 3z = 52

2(58)  (2)(-3.5z) + 3z = 52

116-7z + 3z = 52

116-4z = 52

116-4z-116 = 52-116

-4z=-64

-4z/-4=-64/-4

z=16

x=58-3.5z

x=58-3.5(16)

x=58-56=2

CherieS | 191 days ago