Question: Math

Solve for both systems: - 2x - 3y = 40 and 4x - 3y = 10

In Math | Asked by AnneS2
Answers

- 2x - 3y = 40

- 2x - 3y +3y= 40+3y

-2x=40+3y

-2x/-2=40+3y/-2

x=20-1.5y

4x - 3y = 10

4(20-1.5y) - 3y = 10

4(20)   (4)(-1.5y) - 3y = 10

80-6y - 3y = 10

80-9y = 10

80-9y-80 = 10-80

-9y=-70

-9y/-9=-70/-9

y=7.78

x=20-1.5y

x=20-1.5(7.78)

x=20-11.67=8.33

CherieS | 341 days ago