Question: Math

Factor and solve -1x^2 + 3x + 18 = 0

In Math | Asked by AnneS2
Answers

-1x^2 + 3x + 18 = 0

-1(x^2-3x-18)=0

-1(x    )(x    )   (    -6)(   +3)=0

-(x-6) (x+3) = 0

Solve:

-1(x-6)=0

-1(x)   (-1)(-6)=0

-1x+6=0

-1x+6-6=0-6

-1x=-6

-1x/-1=-6/-1

x=6

Solve:

-1(x+3) = 0

-1(x)   (-1)(+3) = 0

-1x-3=0

-1x-3+3=0+3

-1x=3

-1x/-1=3/-1

x=-3

CherieS | 397 days ago