Question: Math

2x^2 - 32 = 0

Holt McDougal Larson Algebra 1 Common Core Edition page 597 number 4

In Math | Asked by Dee Dee
Asked from the Algebra study pack
Answers

2x^2 - 32 = 0

2(x^2-16)=0

2(x   )(x   )    (   +4)(    -4)=0

2 (x+4)(x-4)=0

Check:

2 (x+4)(x-4)=0

2 (x)(x)  (x)(-4)   (+4)(x)   (+4)(-4)=0

2 (x^2)     -4x        +4x         -16    =0

2(x^2-16)=0

Simplify

2(x-4)=0

2(x-4)/2=0/2

x-4=0

x-4+4=0+4

x=4

Simplify:

2(x+4)=0

2(x+4)/2=0/2

x+4=0

x+4-4=0-4

x=-4

CherieS | 520 days ago