Math

(9x^3z)/(9xzx)x

Asked by AnneS2 on 24 Mar 06:41

Last updated by anonymous on 25 Mar 23:20

1 Answers

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Answered by CherieS on 25 Mar 23:20

=(9x^3z)/(9xz*x)*x

=(9x^3z)/(9x^2z) *x

=9/9=1

=x^3z/x^2z=z/z=1

=x^3/x^2=x^3-2=x

=x*x

=x^2

=x^2