Question: Math

4x^2 - 8x - 4 = 0 Factor and solve

In Math | Asked by AnneS2
Answers

4x^2 - 8x - 4 = 0

4(x^2-2x-1)=0

4 ( (x  )(x  )  (  -2)(   -1))=0

4 ((x-2) (x-1)) = 0

Solve:

4(x-2)=0

4(x)  (4)(-2)=0

4x-8=0

4x-8+8=0+8

4x=8

4x/4=8/4

x=2

Solve:

4(x-1) = 0

4(x)   (4)(-1) = 0

4x-4=0

4x-4+4=0+4

4x=4

4x/4=4/4

x=1

 

x=2,1

 

 

CherieS | 546 days ago