Question: Math

35x^2 + 42x + 7 = 0 Factor and solve for x

In Math | Asked by AnneS2
Answers

35x^2 + 42x + 7 = 0 

7(5x^2+6x+1)=0

7(x   )(5x  )   (    +1)(    +1)=0

7 (x+1) (5 x+1) = 0

Solve:

7 (x+1)=0

(7)(x)  (7)(+1)=0

7x+7=0

7x+7-7=0-7

7x=-7

7x/7=-7/7

x=-1

Solve:

7(5 x+1) = 0

(7)(5x)  (7)(+1)=0

35x+7=0

35x+7-7=0-7

35x=-7

35x/35=-7/35

x=-7/35=-1/5

CherieS | 436 days ago