Question: Math

2x^2 +3x-20=0 Solve

In Math | Asked by AnneS2
Answers

2x^2 +3x-20=0

(x   )(2x   )   (   +4)(   -5)=0

(x+4) (2 x-5) = 0

Solve:

(x+4) =0

x+4-4 =0-4

x=-4

Solve:

(2 x-5) = 0

2 x-5+5 = 0+5

2x=5

2x/2=5/2

x=5/2

CherieS | 483 days ago