Suppose a treadmill has an average accelera- tion of 0.0040 m/s2. How much does its speed change after 4.7 min? Answer in units of m/s.

V = (a • t) + Vi ... where Vi = initial velocity V = [ (0.004) • (282) ] + 2 ... where t = (4.7 min) • (60sec/min) = 282 sec V = 3.1 m/sec ... to two significant figures ∆V = 3.1 − 2 = 1.1 m/sec ... change or increase in velocity