BookRags.com Literature Guides Literature
Guides
Criticism & Essays Criticism &
Essays
Questions & Answers Questions &
Answers
Lesson Plans Lesson
Plans
My Bibliography Periodic Table U.S. Presidents Shakespeare Sonnet Shake-Up
Research Anything:        
History | Encyclopedias | Films | News | Create a Bibliography | More... Login | Register | Help
Not What You Meant?  There are 17 definitions for Peres.  Also try: PPT.

Peres-Horodecki criterion

Print-Friendly
About 2 pages (527 words)

Bookmark and Share Questions on this topic? Just ask!

The Peres-Horodecki criterion is a necessary condition, for the joint density matrix <math>\rho</math> of two systems <math>A</math> and <math>B</math>, to be separable. It is also called the PPT criterion, for Positive Partial Transpose. In the 2x2 and 2x3 dimensional cases the condition is also sufficient. The criterion reads: If <math>\rho</math> is separable, then the partial transpose

<math>\sigma_{m\, \mu\, n\, \nu} := \rho_{n\, \mu\, m\, \nu}</math>

of <math>\rho</math>, taken in some basis <math>|m\rangle_A \otimes |\mu\rangle_B </math>, has non negative eigenvalues. In matrix notation, if we write a N X M mixed state ρ as block matrix:

<math> \rho =

\begin{bmatrix} \rho _{11} & \cdots & \rho _{1 n}\\ \vdots & \ddots & \vdots \\ \ \rho _{n 1} & \cdots & \rho _{n n} \end{bmatrix} </math> ,where each <math>\rho _{i : j} </math> is M X M and n runs from 1 to N. The partial transpose of ρ is then given by

<math> \rho ^{PT} =

\begin{bmatrix} \rho ^T _{11} & \cdots & \rho ^T _{1 n}\\ \vdots & \ddots & \vdots \\ \ \rho ^T _{n 1} & \cdots & \rho ^T _{n n} \end{bmatrix} </math> So ρ is PPT if <math>( I \otimes T ) (\rho) </math> is positive, where T is the transposition map on matrices. That necessity of PPT for separability follows immediately from the fact that if ρ is separable, then <math>( I \otimes \Phi ) (\rho) </math> must be positive for all positive maps Φ. The transposition map is clearly a positive map. Showing that being PPT is also sufficient for in the 2 X 2 and 2 X 3 (therefore 3 X 2) cases is more involved. It was shown by the Horodecki's that for every entangled state there exists an entanglement witness. This is a result of geometric nature and invokes the Hahn-Banach theorem (see reference below). From the existence of entanglement witnesses, one can show that <math>( I \otimes \Phi ) (\rho) </math> being positive for all positive maps Φ is not only necessary but also sufficient for separability of ρ. Furthermore, every positive map from the C*-algebra of <math>2 \times 2</math> matrices to <math>2 \times 2</math> or <math>3 \times 3</math> matrices can be decomposed into a sum of completely positive and completely copositive maps. In other words, every such map Λ can be written as

<math>\Lambda = \Lambda _1 + \Lambda _2 \circ T</math>

,where <math>\Lambda_1</math> and <math>\Lambda_2</math> are completely positive and T is the transposition map. Combining the above two facts, we can conclude PPT is also sufficient for separability in the 2 X 2 and 2 X 3 cases. Due to the existence of non-decomposable positive maps in higher dimensions, PPT is no longer sufficient in higher dimensions. In higher dimension, there are entangled states which are PPT. Such states have some interesting properties including the fact that they are bound entangled, i.e. they can not be distilled for quantum communication purposes.

References

View More Summaries on Peres-Horodecki criterion
 
Ask any question on Peres-Horodecki criterion and get it answered FAST!
Answer questions in BookRags Q&A and earn points toward
discounted or even FREE Study Guides and other BookRags products!
Learn more about BookRags Q&A
Copyrights
Peres-Horodecki criterion from Wíkipedia. ©2006 by Wíkipedia. Licensed under the GNU Free Documentation License. View a list of authors or edit this article.

Article Navigation
Join BookRagslearn moreJoin BookRags




About BookRags | Customer Service | Report an Error | Terms of Use | Privacy Policy