Math t^2+2t-19=5 Factor and solve Asked by AnneS2 on 06 Jul 03:55 Last updated by anonymous on 07 Jul 13:28

t^2+2t-19=5 t^2+2t-19-5=5-5 t^2+2t-24=0 (t )(t ) ( -4)( +6)=0 (t-4) (t+6) = 0 Solve: (t-4) =0 t-4+4=0+4 t=4 Solve: (t+6) = 0 t+6-6=0-6 t=-6