Math Solve for each system: 2v+4x+2z = 24, 4v+x = 16, 6v=18 Asked by AnneS2 on 22 Aug 07:10 Last updated by anonymous on 23 Aug 08:10

6v=18 6v/6=18/6 v=3 4v+x = 16 4(3)+x = 16 12+x = 16 12+x-12 = 16-12 x=4 2v+4x+2z = 24 2(3)+4(4)+2z = 24 6+16+2z = 24 22+2z = 24 22+2z-22 = 24-22 2z=2 2z/2=2/2 z=1