Math Solve for both systems: x = y + 2 and 3x + 3y = 12 Asked by AnneS2 on 11 Oct 07:54 Last updated by anonymous on 12 Oct 10:38

x = y + 2 3x + 3y = 12 3(y + 2 ) + 3y = 12 3(y) (3)( + 2 ) + 3y = 12 3y+6+3y=12 6y+6=12 6y+6-6=12-6 6y=6 6y/6=6/6 y=1 x = y + 2 x = 1+ 2 =3