Math

(n^2 -n-29) / (n-6)=

Asked by AnneS2 on 05 Aug 05:45

Last updated by anonymous on 06 Aug 11:37

1 Answers

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Answered by CherieS on 06 Aug 11:37

(n^2 -n-29) / (n-6)=n+5 r. 1

(n-6)(n+5)

(n)(n) (n)(5) (-6)(n) (-6)(5)

n^2 +5n -6n -30

n^2-n-30

n^2-n-29

-n^2+n+30

1