Question: Math

(n^2 -n-29) / (n-6)=

In Math | Asked by AnneS2
Answers

(n^2 -n-29) / (n-6)=n+5 r. 1

(n-6)(n+5)

(n)(n)  (n)(5)  (-6)(n)  (-6)(5)

n^2      +5n     -6n        -30

n^2-n-30

 

n^2-n-29

-n^2+n+30

           1

 

CherieS | 357 days ago