Question: Math

Solve for both systems 5x + 2y = 12 and 3x + 2y = 12

In Math | Asked by AnneS2
Answers

5x + 2y = 12

5x -5x+ 2y = 12-5x

2y = 12-5x

2y/2 = 12-5x/2

y=6-2.5x

3x + 2y = 12

3x + 2(6-2.5x) = 12

3x + 2(6)   (2)(-2.5x) = 12

3x+12-5x=12

12-3x=12

12-3x-12=12-12

-3x=0

-3x/-3=0/-3

x=0

y=6-2.5x

y=6-2.5(0)

y=6-0=6

CherieS | 491 days ago