Question: Math

How many gal. of a 40% sugar solution must be mixed with 9 gal. of pure water to make a 23% solution?

In Math | Asked by AnneS2
Answers

9 gal=amount of water to be added with 0% concentration of sugar

x=gal of 40% sugar solution

23%=final solution

(9gal)(0)+(x)(40%)=23%(x+9gal)

0+(x)(40%)=23%(x+9gal)

0+(x)(40%)=23%(x)  (23%)(+9gal)

(x)(40%)=23%(x) + (207%gal)

(x)(40%)-23%x=23%(x)-23%x + (207%gal)

17%x=207%gal

17%x/17%=207%gal/17%

x=12.18gal

CherieS | 296 days ago