Math

2x^2 +3x-20=0 Solve

Asked by AnneS2 on 22 May 06:23

Last updated by anonymous on 23 May 11:10

1 Answers

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Answered by CherieS on 23 May 11:10

2x^2 +3x-20=0

(x )(2x ) ( +4)( -5)=0

(x+4) (2 x-5) = 0

Solve:

(x+4) =0

x+4-4 =0-4

x=-4

Solve:

(2 x-5) = 0

2 x-5+5 = 0+5

2x=5

2x/2=5/2

x=5/2