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Question: Math

(2x^2 -17x-38) / (2x+3)=

In Math | Asked by AnneS2
Answers

(2x^2 -17x-38) / (2x+3)=x-10 R. -8

(2x+3)(x-10 )

(2x)(x)  (2x)(-10)  (3)(x)  (3)(-10)

2x^2        -10x         +3x       -30

2x^2         -7x  -30

-(2x^2-7x-30)=-2x^2+7x+30

 

2x^2 -17x-38

-2x^2+7x+30

                -8

CherieS | 255 days ago