Question: Math

1x^2 + 1x - 42 = 0 Factor and solve

In Math | Asked by AnneS2
Answers

1x^2 + 1x - 42 = 0

(x   )(x   )   (   -6)(   +7)=0

(x-6) (x+7) = 0

Solve:

(x-6)=0

x-6+6=0+6

x=6

Solve:

(x+7) = 0

x+7-7 = 0-7

x=-7

CherieS | 373 days ago